((9-3x)/(1-2))^2=-1

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Solution for ((9-3x)/(1-2))^2=-1 equation: 


x in (-oo:+oo)

((9-(3*x))/(1-2))^2 = -1 // + 1

((9-(3*x))/(1-2))^2+1 = 0

((9-3*x)/(1-2))^2+1 = 0

((9-3*x)^2)/((-1)^2)+1 = 0

((9-3*x)^2)/((-1)^2)+(1*(-1)^2)/((-1)^2) = 0

(9-3*x)^2+1*(-1)^2 = 0

9*x^2-54*x+82 = 0

9*x^2-54*x+82 = 0

9*x^2-54*x+82 = 0

DELTA = (-54)^2-(4*9*82)

DELTA = -36

DELTA < 0

1 = 0

1 = 0

1 = 0

x belongs to the empty set

x belongs to the empty set

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